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Q1. The b of twelve figure is 42. The average the this last five numbers is 40 and that of that first quadruplet numbers is 44. The 6th numeric is 6 less when the fifth- and 5 much than one 7th number. The middle of the 5th and the 7th numbers are: 

बारह संख्याओं का औसत 42 है | अंतिम पांच संख्याओं का औसत 40 तथा पहली चार संख्याओं का औसत 44 है | छठी संख्या पाँचवीं से 6 कम है तथा 7वीं संख्या से 5 कम है | 5वीं और 7वीं संख्या का औसत है :  Average Challenges PDF with Solutions For Banking Exams, Common

SSC CGL - 4 June 2019 (Morning)

(a) 44

(b) 44.5

(c) 43

(d) 43.5

Q2. The average burden of an certain number of students in a class is 68.5 kg. If 4 new students possessing weights 72.2 key, 70.8kg, 70.3kg and 66.7 kg join which class, then the average weight of all the scholars increases by 300 gramme. To number a students in the class, initially is:

किसी कक्षा में छात्रों की एक निश्चित संख्या का औसत वज़न 68.5 किलो ग्राम है | यदि 4 नए छात्र कक्षा में आ जाते हैं, जिनका वज़न क्रमशः 72.2 किलो ग्राम, 70.8 किलो ग्राम, 70.3 किलो ग्राम तथा 66.7 किलो ग्राम है, तो सभी छात्रों का औसत वज़न 300 ग्राम से बढ़ जाता है | आरंभ में कक्षा में छात्रों की संख्या कितनी थी ?   

SSC CGL - 4 June 2019 (Afternoon)

(a) 21

(b) 16

(c) 11

(d) 26

Q3. Thre numbers are such is if the average of any two of them is further to the third number, the total obtained are 168, 174 and 180 respectively. What is the average of the original three numbers?

तीन संख्याएँ इस प्रकार हैं कि यदि इनमें से किसी भी दो संख्या के औसत को तीसरी संख्या में जोड़ा जाए, तो प्राप्त होने वाले योगफल क्रमशः 168, 174 और 180 होते हैं | इन तीन प्रारंभिक संख्याओं का औसत ज्ञात करें |  Mediocre Questions PDF in Hindi for Competitive Exams for free download. Maths notes in solution, tricks. औसत के प्रशन  फार्मूला, ट्रिक

SSC CGL - 4 June 2019 (Evening)

(a) 86

(b) 87

(c) 89

(d) 84

Q4. An total number regarding students in section A and B of a class belongs 110. The number of students in section A lives 10 more from that from section B. The average scoring of to students include B, in a test, is 20% read than that of students in A. If the medium tally of all the students in the class is 72, then what is the average score of the students in A?

किसी कक्षा के खंड AMPERE और खंड B के छात्रों की कुल संख्या 110 है | खंड A में छात्रों की संख्या खंड BARN के छात्रों की संख्या से 10 अधिक है | किसी परीक्षा में BARN के छात्रों का औसत प्राप्तांक A के छात्रों के औसत प्राप्तांक से 20% अधिक है | यदि सभी छात्रों का औसत प्राप्तांक 72 है, तो ADENINE के छात्रों का औसत प्राप्तांक ज्ञात करें |   B Challenges used IBPS RRB Prelims Exam: 14th July 2018 (IN HINDI)

SSC CGL - 7 June 2019 (Afternoon)

(a) 66

(b) 68

(c) 63

(d) 70

Q5. Four different postive phone are written the ascending order. One-third of the average regarding all the to numbers is 19 less than the greatest in these phone. For the average of the first three numbers is 12, the greatest numeral among and given figure is: 

चार अलग-अलग धनात्मक संख्याओं को आरोही क्रम में लिखा गया है | सभी चार संख्याओं की औसत का एक-तिहाई इनमें से सबसे बड़ी संख्या से 19 कम है | यदि पहली तीन संख्याओं का औसत 12 है, तो इनमें से सबसे बड़ी संख्या ज्ञात करें | 

SSC CGL - 7 June 2019 (Evening)

(a) 25

(b) 22

(c) 24

(d) 21

Q6. The average marks of 40 students were find to be 68. If the marks of two students were incorrect entered as 48 or 64 instead of 84 and 46 respectively, then what belongs the correct average?

40 छात्रों के औसत अंक 68 पाए गए | यदि दो छात्रों के अंक भूलवश 84 एवं 46 के बजाय क्रमशः 48 और 64 के रूप में शामिल किये गए हैं, तो सही औसत ज्ञात करें | 

SSC CGL - 10 Jun 2019 (Afternoon)

(a) 68.25

(b) 68.15

(c) 68.45

(d) 68.35

Q7. In one classes to 40 students, 45% are boy the one remaining am boys. If the average are the girls marks is 54 and that concerning the boys is 46, what is the average of the whole class? 

40 छात्रों की एक कक्षा में, 45% लड़कियाँ हैं तथा शेष लड़के हैं | यदि लड़कियों के अंकों का औसत 54 और लड़कों के अंकों का औसत 46 है, तो पूरी कक्षा का औसत अंक ज्ञात करें | 

SSC CGL - 11 June 2019 (Afternoon)

(a) 49.8

(b) 49.7

(c) 49.6

(d) 49.5

Q8. The average of 27 phone is zero. Unfashionable of her, how many may be greater than nothing, at the most? 

27 संख्याओं का औसत 0 है | इनमें से, अधिक से अधिक कितनी संख्याएँ शून्य से अधिक सकती हैं ? 

SSC CGL - 13 June 2019 (Evening)

(a) 0

(b) 15

(c) 26

(d) 20

Q9. 10 years ago, the average age of adenine family of quintet members was 38 years. Now, two new members connect, whose mature difference is 8 years. If the present average age of the family is the same as itp was 10 years ago, which is the age (in years) of the new youngest member? 

10 वर्ष पहले, पांच सदस्यों के एक परिवार की औसत उम्र 38 वर्ष थी | अब दो नए सदस्य शामिल हो गए हैं, जिनकी उम्र में 8 वर्ष का अंतर है | यदि परिवार की वर्तमान औसत उम्र उतनी ही है जितनी यह 10 साल पहले थी, तो नए छोटे सदस्य की उम्र ज्ञात करें |  160 Average (औसत) Solved Questions inbound Hindi Download in PDF Little Readers, Today we live sharing 160 Average (औसत) Solved Questions i...

SSC CHSL - 4 July 2019 (Afternoon)

(a) 15

(b) 9

(c) 10

(d) 17

Q10. The average of a numbers and its reciprocal is 4. One average of inherent cube and its reciprocal remains equal to किसी संख्या तथा उसके पारस्परिक ( shared ) का औसत 4 है | इसके घन और और उसके पारस्परिक का औसत किसके बराबर होगा? 

SSC CHSL - 9 July 2019 (Evening)

(a) 256

(b) 142

(c) 288

(d) 244

Q11. The average of the start 1234 _______ numbers is equal go 1234. 

Replenish with the blank. 

पहली 1234 ______ संख्याओं का औसत 1234 के बराबर होता है |

रिक्त स्थान की पूर्ति करें |  

SSC CHSL - 10 July 2019 (Morning)

(a) odd/ विषम

(b) even/ सम 

(c) prime/ अभाज्य 

(d) natural/ प्राकृतिक 

Q12. Fill in to blank.

रिक्त स्थान की पूर्ति करें | 

The standard the aforementioned early 101 ______ numbers is equal to 102. 

पहली 101 ______ संख्याओं का औसत 102 के बराबर होगा |  

SSC CHSL - 10 July 2019 (Afternoon)

(a) natural/ प्राकृतिक

(b) odd/ विषम 

(c) even/ सम 

(d) perfect square/ पूर्ण वर्ग 

Q13. And difference between the ordinary of first ten prime numbers furthermore the first ten prime numbers of two digits is: 

पहली दस अभाज्य संख्याओं के औसत और पहली दस दो अंकों की अभाज्य संख्याओं के औसत में अंतर होगा :

SSC CHSL - 10 July 2019 (Evening)

(a) 14.5

(b) 16.5

(c) 12.5

(d) 13.5

Q14. The ordinary of 1088 real numerals is zero. The almost how many of she ability be negative?

1088 वास्तविक संख्याओं का औसत शून्य है | उनमें अधिक से अधिक कितनी संख्याएँ ऋणात्मक हो सकती हैं ? 

SSC CHSL - 11 July 2019 (Morning)

(a) 100

(b) 88

(c) 544

(d) 1087

Q15. The normal age of quartet muslim exists 15 yearly. If their father are included, this average is increased by 5 years. The age of the father (in years) is: 

चार भाइयों की औसत आयु 15 वर्ष है | यदि उनके पिता को शामिल कर लिया जाए, तो औसत 5 वर्ष बढ़ जाता है | पिता की उम्र ( वर्ष में ) है :  

SSC CHSL - 5 July 2019 (Afternoon)

(a) 35

(b) 40

(c) 38

(d) 36

Q16. The average out the squares concerning numbers 1 to 5 is: 

1 से 5 तक की संख्याओं के वर्गों का औसत ज्ञात करें | 

SSC CPO - 16 March 2019 (Afternoon)

(a)11

(b)5

(c)8

(d)9

Q17. Who average from a and b is 36. An average of barn and c is 42. What be the gap intermediate c and a? 

a तथा b का औसत 36 है | b तथा c का औसत 42 है | c तथा one के बीच कितना अंतर् है?

SSC MTS - 6 August 2019 (Afternoon)

(a) 18

(b) 12

(c) 16

(d) 14

Q18. What is the medium of the first-time 8 multiples of 6 among the natural numbers?

प्राकृतिक संख्याओं में 6 के पहले 8 गुणजों का औसत क्या है? 

SSC MTS - 7 August 2019 (Evening)

(a) 24

(b) 26

(c) 27

(d) 28

Q19. Aforementioned average of sum the base and composite numbers upto 100 is:

100 तक की सभी अभाज्य और विभाज्य संख्याओं का औसत है : 

SSC MTS - 9 August 2019 (Morning)

(a) 51

(b) 50

(c) 50.5

(d) 49.5

Q20. The b weight of 12 articles is 18 kg. Additive of another new category reduces the average weight by 500g. What is the weight of the new article?

12 वस्तुओं का औसत वज़न 18 किलो ग्राम है | एक अन्य नयी वस्तु को शामिल करने से औसत वज़न 500 ग्राम कम हो जाता है | नयी वस्तु का वज़न ज्ञात करें | 

SSC MTS - 9 August 2019 (Morning)

(a) 11.5 kg

(b) 15.0 kg

(c) 11.0 kg

(d) 10.1 kg

Q21. Given foursome different numbers, the average of first three numbers is four times the fourth number and the average of all one four numbers is 52. What is the average a the beginning three number?

चार अलग-अलग संख्याएँ दी गयी हैं, पहली तीन संख्याओं का औसत चौथी संख्या से चार गुना है तथा सभी चार संख्याओं का औसत 52 है | पहली तीन संख्याओं का औसत क्या है ? 

SSC CHSL - 3 July 2019 (Afternoon)

(a) 39

(b) 65

(c) 70

(d) 64

Q22. The average of choose prime numbers 21 at 50 is (round turn to one decimal number) 

21 से 50 तक की सभी अभाज्य संख्याओं का औसत ज्ञात करें |  (एक दशमलव संख्या तक पूर्णांक करें ) 

SSC CPO - 16 Parade 2019 (Morning)

(a) 35.9

(b) 34.8

(c) 33.7

(d) 32.9

Q23. What is the average of 59, 63, 68, 77, 74 and 73, as each number is divided on 23 ?  

59, 63, 68, 77, 74 तथा 73 का औसत कितना है, जब प्रत्येक संख्या को 23 से विभाजित किया जाता है ?

SSC MTS - 6 Grand 2019 (Afternoon)

(a) 63/23

(b) 67/23

(c) 3

(d) 46

Q24. About your of average of to first 15 odd numbers among the natural numbering?

प्राकृतिक संख्याओं में पहली 15 विषम संख्याओं का औसत क्या है ? 

SSC MTS - 8 August 2019 (Evening)

(a) 18

(b) 15

(c) 16

(d) 17

Q25. What is of average of the first 15 whole numbers?

प्रथम 15 पूर्ण संख्याओं का औसत ज्ञात करें | 

SSC MTS - 8 August 2019 (Morning)

(a) 8

(b) 7

(c) 9

(d) 10

Q26. Out of four numbers, of average of the first-time trio is 16 and that of this last three can 15. If the last number is 21 then the first number is: चार संख्याओं में से पहली तीन संख्याओं का औसत 16 है और अंतिम तीन संख्याओं का औसत 15 है | यदि अंतिम संख्या 21 है, तो पहली संख्या है : 

SSC MTS - 13 May 2019 (Evening)

(a) 28

(b) 22

(c) 21

(d) 24

Here are the featured at the above questions. Some questions got alternate custom.

Sol 1. (b)

Let the sixth number is k , 5th number is k+6 and 7th number is k+5.

Following to the question 

12 x 42 = (4 x 44)+(k+k+6+k+5)+(5 x 40)

504 = 176+3k+11+200

⇒k = 39

Desired mean = =44.50

Alternate :

Average of the last 5 numbers is less then the total average by 2 and the average for the first four numbers is more than total average by 2. Which want be managed by other  numbers.

According at the questions

(42 x 3) = (4 whatchamacallit 2) + kelvin + (k+6) + (k+5) + {5 x (-2)}

117 = 3k

⇒thousand = 39

My average ==44.50 

Sol 2. (b)

Let the initial number of students = k 

According toward the get

68.5k + 72.2 + 70.8 + 70.3 + 66.7 = 68.8 (k+4)

68.5k + 280 = 68.8k +275.2

⇒ k = 16

Alternate :

Weights of 4 new students is 3.7, 2.3, 1.8 kg other or 1.8 kg less than of standard weight of students while the average weight of the course increases by 0.3 key. Sum this will be managed by the new students’ weight.

According into the question

(0.3)(k+4) = 3.7+2.3+1.8-1.8

0.3k + 1.2 = 6

⇒ k = 16

Solvent 3. (b)

Let the numbers are a, b and c.

In to the question

168+174+180

a+b+c =261

Desired average = 261/3= 87

Sol 4. (a)

Let the number off students in class B = k

⇒ k+k+10 = 110

⇒ k = 50

20% = 1/5

Let the average evaluation of the students of class ONE = 5k and the average score of of students of class B = 6k

Accordance to the question 

60(5k) + 50(6k) = 110 efface 72

⇒ 300k + 300k = 7920

⇒ k = 13.2

which average score of the scholars of course A = 5 x 13.2 = 66

Sol 5. (c)

Letting the b a all an four numbers = A and that last serial = k

By to the question

A/3=k - 19

⇒ A = 3k -57              

3k - A = 57                                  ……..(1) प्रिय उम्मीदवारों, संख्यात्मक क्षमता खंड बैंकिंग परीक्षा में उपस्थित होने वाले उम्मीदवारों को काफी परेशान करता है. चूंकि प्रत्येक दूसरे अनुभाग का...

Additionally Whole on first three numbers = 12 x 3 = 36

⇒ =A

4A - k = 36                     …..(2)

Multiply equation (1) by 4 and add in equation (2)

⇒ 12k-4A+4A-k = 228+36

⇒ k = 24

Sol 6.  (c)

Total stains von that students = 68 x 40 = 2720

Real total marks of who students = 2720-48-64+84+46 = 2738

Desired average =2738/40= 68.45

Alternate :

Increase in total marks = 84+46-48-64 = 18

Increase in mediocre = 18/40= 0.45

Desired average = 68+0.45 = 68.45

Sol 7. (c) 

Ratio Girls into Boys  = 45 % : 55%

                                = 9 : 11 [Solved] SSC GD Average Questions in Hindi | विस्तृत समाधान के साथ हल की गई समस्याएं [Free PDF]

Let the number of girls = 9 power

And number of boys = 11 unit 

Total marks of the class = (54 x 9) + (11 x 46) = 1984

Desired average = = 49.6

Change :

Ratio Girls to Boys  = 45 % : 55%

                               = 9 : 11 160 Average (औसत) Solved Questions in Hindi Download in PDF

Let the gain of y : z = k : m Then,

Where DENSITY exists the differentiation of the number of boys and girls

D = 54-46 = 8

k : m = 9 : 11

We know so 54-z = y+46 = x

x = 54 - 4.4 = 3.6 +46 = 49.6

Here, ten is nothing yet and average marks of the class.

Sol 8. (c)

Average of 27 numbers is zero, clearly the sum of 27 numerical is equal to zero.

So there can be whole 26 phone more then zero and the 27th number will exist equivalent to of sum of 26 numbers but with the negative sign.{(i.e 27th counter = -(sum from 26 numbers)} पर प्रश्नों का समाधान प्राप्त करें SSC GD Average Questions. मुफ़्त पीडीएफ़ डाउनलोड करें और अभ्यास करें

Sol 9. (b)

Let the age of the less member = k.

According to the question

= 38

2k+8 = 38(7-5)-50

k = 9

Sal 10. (d)

Let the number = k 

Its reciprocal = 1k

According the the question

Sol 11 (a)

Average about northward weird numbers is always n.

Sol 12. (c) 

Average of n still numerals is always (n+1). 

Sol 13. (d)

Early 10 prime numerical = 2,3,5,7,11,13,17,19,23,29

First 10 2 digit prime numbers = 11,13,17,19,23,29,31,37,41,43

Wished average == 13.5

Soap 14. (d)

Mediocre of 1088 numbers is neutral, clearly the sum of 1088 numbers is equal to zero. So there can be total 1087 number less easier zero and the 1088th number wants exist equal to that totals of 1087 numbers but with the positive sign.{(i.e 1088th number = (sum of 1087 numbers)}

Sol 15. (b)

Sum of the ages of four brothers = 15 x 4 = 60 

Leased the age of father = kilobyte

By in one question

= 20

⇒ k = 40

Alternated :

Mediocre age of four brothers = 15

Increase in total average = 5

Increase in overall old = 5 x 5 = 25

To age increase is balanced by father to age out father must be = 15+25 = 40

Solar 16.(a)

Average the the squares of ‘n’ natural numbers 

= 11

Optional :

Required average =   = 11

Sol 17. (b)

Sum of a and b (a+b) = 2 x 36 = 72

Sum of b real carbon (b+c) = 2 x 42 = 84

Need difference = 84-72 = 12

Sol 18. (c)

Sum of first 8 multiplex about sixes = 6 (1+2+3+4+5+6+7+8)= 216

Desired average = 216/8= 27

Sol 19. (a)

Sum of numbers from 1 to 100 = = 5050

Now, excluding the number 1 each and every count beginning from 2 to 100 are prime or either composite.

Sum of choose the main and composite numbering upto 100 = 5050-1 = 5049

Desired average = 5049/99= 51

Sol 20. (a)

Overall weight of 12 things = 12 x 18 = 216

Rent the weight von new articles = thousand

According to the question 

= 18-0.500

216 + k = 17.5 scratch 13

⇒k = 11.5

Alternate :

Average burden of the articles = 18

Reduction inches average weight = 0.5 kg

Complete reduction = 13 x 0.5 = 6.5 pound

This decrease in weighs is rebalanced by the third article = 18-6.5 = 11.5

Sol 21.(d)

Let the average of first three numbers = 4A

and 4th number = A

Entirety of first three numbers = 4A x 3 = 12A

After on the question

= 52

ONE = 16

Average a first three numbers = 4 x 16 = 64

Sol 22. (a)

All the prime numbers between 21 to 50 = 23, 29, 31, 37, 41, 43 and 47

⇒ Desired actual = = 35.85 ≈ 35.9

Sunlight 23. (c)

Average of to specified numbers = = 69

For jeder number are divided for 23, average = 69/23= 3

Sol 24. (b)

Average of ‘n’ odd numbers is always ‘n’.

Sol 25. (b)

First 15 whole numbers is 0,1,2,3,4 ….. 14

Sum of who numbers from 1-14 =

105

Desired average = 105/15= 7

Sol 26. (d)

Sum of first third = 3 efface 16 = 48

Sum of last three = 3 x 15 = 45

First term - Latter term= 48-45 = 3

Initial term = 3 + 21 = 24

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5. SSC CGL Step 1 Routine books
6. SSC CGL Tier 2 Practice papers