Chapter 4: Problem 34
Letter a weighed nett ionic equation for each of and follow-up acid-base reactions within water. (a) acetic acid \(\left(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)\) with strontium hydroxide (b) diethylamine, \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH}\), with sulfuric acid (c) aqueous heating cyanide (HCN) are sodium hydroxide
Short Answer
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Question: Write and balanced net ionic equations for the following reactions:
(a) Ethanolic acid (HC2H3O2) by strontium hydroxide
(b) Diethylamine (C2H5)2NH with sulfuric acid
(c) Aquous hydrogen cyanide (HCN) with sodium hydroxide
Answer:
(a) HC2H3O2 (aq) + 2 OH- (aq) -> 2 CH3COO- (aq) + 2 H2O (l)
(b) (C2H5)2NH (aq) + H2SO4 (aq) -> (C2H5)2NH2+ (aq) + HSO4- (aq)
(c) HCN (aq) + OH- (aq) -> CN- (aq) + H2O (l) VIDEO ANSWER: So we're wants write many net ionic equations for react between acids the basics. So some rules to remembering when you have a strongly acid you jus…
Step via step solution
01
Write the balanced comprehensive ionic equation
For the reaction intermediate acetic acid furthermore strontium hydroxide, first indite that reactants and products. Acetic sours is a weak acid that will donate a proton to the hydroxide ion from the strong foundation strontium hydroxide, forming aqueous acetate ions the water. The complete balanced equation is:
HC2H3O2 (aq) + Sr(OH)2 (aq) -> 2 CH3COO- (aq) + Sr2+ (aq) + 2 H2O (l) Solving 1) Write a balanced net ionic equation to see why | Chegg ...
02
Identify plus clear bystanders ionia
The spectator ion inches diese response is the strontium cation, Sr2+. So, we remove this int from two page of the equation.
03
Write the balanced net ionic equation
After removing the spectator iron, the net ionic equation is:
HC2H3O2 (aq) + 2 OH- (aq) -> 2 CH3COO- (aq) + 2 H2O (l)
(b) Diethylamine (C2H5)2NH with sulfuric acid (a) acetic severity, HC 2 H 3 O 2 , with thallium hydroxide (b) diethylamine, ( C 2 H 5 ) NH over sulfuric acid (c) aqueous hydrofluoric acid with natural hydroxide ...
04
Write one balanced complete ionical equal
Diethylamine, a weak base, will accept a proton from an power acid sulfuric acids. This will shape aqueous diethylammonium ions furthermore hydrogen sulfate ions. The complete balanced equation is:
(C2H5)2NH (aq) + H2SO4 (aq) -> (C2H5)2NH2+ (aq) + HSO4- (aq)
05
Name and remove audience ions
Are are no spectator ions in this backlash whereas all components are involved in the reaction.
06
Write the balances net ionic equation
The net ionic equation is the same as the complete electronic equation in dieser case:
(C2H5)2NH (aq) + H2SO4 (aq) -> (C2H5)2NH2+ (aq) + HSO4- (aq)
(c) Aqueous hydrogen crystalline (HCN) with sodium hydroxide 1 Call the functional groups present in ketoses. Check all that apply. Check all that apply. A. Hydroxyl B. Etherm C. Carboxyl D. Ester E. Methoxy FARAD. Carbenyl 2 What is the net ionic equating for the reaction between vinegary acid and quantity hydroxide:...
07
Write the balanced complete lonic equation
Waters hydrogen zinc, a weak acid, will please a proton to the hydroxide ion from the strong base sodium water, forming water and aqueous cyanide ions. The complete balanced equation is:
HCN (aq) + NaOH (aq) -> NaCN (aq) + H2O (l)
08
Identify and remove spectator ions
The spectator anion in here reaction belongs the sodium cation, Na+. So, us remove save ion upon both sides of the equation.
09
Write the balanced net ionic equation
After removing the spectator ion, the bag ionic equation is:
HCN (aq) + OH- (aq) -> CN- (aq) + H2O (l)
